Assuming wind speed is 10 m/s, the turbine drag is 70 N, the elevation angle is 60 degrees, the kite area is 4 m², the wind turbine would be 1.2 m² and its drag would be equivalent to a 1 m² area perpendicular to the wind and with a drag coefficient of 1.
60 degrees should mean an L/D ratio of 2, that with the wind turbine.
Now what is the L/D ratio of the kite alone? Let us take the elevation angle value of 67 degrees from @Tallakt’s assessment, so a L/D ratio of 2.5 (the cosine is 0.3907), then see how it can work.
Let us try with a reasonable lift coefficient of 1, so a drag coefficient of 0.4:
Lift = 1/2 X 4 [kite area] x 1.2 [air density] X 1 [lift coefficient] X 100 [squared wind speed] = 240 N.
Drag = 96 N.
The L/D ratio with the turbine (adding 70 N) is 240/166. That doesn’t work as this value is far below 2. Or that suggests a cosine of 1: (240/166) = 0.69, so an elevation angle of 46 degrees, or a higher angle value than 67 degrees for the kite alone or another variable to be changed.
Now let us try with a yet reasonable lift coefficient of 1.6, so a drag coefficient of 0.64:
Lift = 1/2 X 4 [kite area] x 1.2 [air density] X 1.6 [lift coefficient] X 100 [squared wind speed] = 384 N.
Drag = 153.6 N.
The L/D ratio with the turbine (adding 70 N) is 384/223.6. That suggests a cosine of 1: (384/223.6) = 0.58, so an elevation angle of 54 degrees. It is better but not still 60 degrees.
In fact that works from a very high (although not impossible) lift coefficient of 2.9, implying a high drag coefficient of 1.16:
Lift = 1/2 X 4 [kite area] x 1.2 [air density] X 2.9 [lift coefficient] X 100 [squared wind speed] = 696 N.
Drag = 278.4 N.
The L/D ratio with the turbine (adding 70 N) is 696/348 = 2. It looks correct now.
One question was also a comparison with a tilted rotor like Daisy.
For it let us evaluate Kiwee-one with the same angle as Daisy, so about 35 degrees, that on the basis of the last numbers, using 2.9 for the lift coefficient as this coefficient would allow to reach 60 degrees with the turbine.
35 degrees should mean 1: (0.8191) = 1.22 for the L/D ratio, so 696/570.
570 – 278 = 292 N, so a little more than 4 turbines (70 N X 4) in all.
Now we extrapolate from the second calculation with a lift coefficient of 1.6.
35 degrees should mean 1: (0.8191) = 1.22 for the L/D ratio, so 384/315.
315 – 153 = 162 N, so more than 2 turbines (70 N X 2) in all.
This can be wrong, so please correct me. Probably some variables should be a little different and known in order to obtain a more precise calculation.
Even only two turbines for a kite of 4 m² at 35 degrees would mean a good efficiency (power to weight ratio) of this system. And it could be four turbines. The weight (0.5 kg per turbine) is not yet taken account but looks to be low in regard to the lift of the kite at 10 m/s wind speed.
For what I see, an installation with tilted rotors would have an equivalent efficiency (power to weight ratio) in small scale but this topic should be deeply studied.