Betz limit and power available in the wind

I get an efficiency of 0.24 for dragging a parachute at 1/3 wind speed and a drag coefficient of 1.62

Which is ~0.4 of Betz efficiency, and approx. half the mechanical efficiency of high end lift wind turbines.

I doubt that the same formulae are directly transferable to a lifting kite because, as in propeller-lift turbines, it has to account for swept area. e.g. doubling the wing’s aspect ratio also doubles the swept area, increases L/D ratio, etc..

Take a sail boat moving in a straight line pulled by a lifting kite, how is the “drag-equivalent efficiency” computed and why would it matter

PS just for reference 1sqm 10m/sec, 1.2kg/mc:

  • 10 ** 3 / 2 * 1.2 -= 600watt raw power in the airflow
  • 600 * .59 = 354 watt remaining since Betz is an asshole.
  • 144 watt from a 1sqm parachute dragging the line at 3.333m/sec and 1.62 drag coefficient